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2x^2+6x=1400
We move all terms to the left:
2x^2+6x-(1400)=0
a = 2; b = 6; c = -1400;
Δ = b2-4ac
Δ = 62-4·2·(-1400)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11236}=106$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-106}{2*2}=\frac{-112}{4} =-28 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+106}{2*2}=\frac{100}{4} =25 $
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